CS
Algorithms (3)
U 2R' 2D2 2R U' 2R' 2D2 2R
My choice
14 HTM · 8 STM · 18 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 19 solvers' sheets
U' Rw' 2L U 2R U' 2L' U 2R' U' Rw U
16 HTM · 12 STM · 16 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
Uw' B 2R B' 2L' B 2R' B' 2L Uw
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U' Rw' U 2R U' 2L U 2R' U' 2L' Rw U. Every algorithm above was run by our logic engine from that state and reaches "solved".