CO
Algorithms (3)
U 2R' 2D' 2R U' 2R' 2D 2R
My choice
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 22 solvers' sheets
2B 2R B' 2R' 2B' 2R B 2R'
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
<R,B>
One hand: needs L, B, S or E
Cubemuch
R 2F R' 2B' R 2F' R' 2B
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<R,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2R B' 2R' 2B 2R B 2R' 2B'. Every algorithm above was run by our logic engine from that state and reaches "solved".