AD
Algorithms (3)
Rw2 2F2 U 2R2 U' 2F2 U 2R2 U' Rw2
My choice
14 HTM · 10 STM · 24 QTM
3-gen
rotationless
<U,R,F>
One hand: R, U and M with F or D
Cubemuch
Lw2 2B2 Dw 2R2 Dw' 2B2 Dw 2R2 Dw' Lw2
14 HTM · 10 STM · 24 QTM
rotationless
<R,D,L,B>
One hand: needs L, B, S or E
Cubemuch
Lw2 2B2 D 2R2 D' 2B2 D 2R2 D' Lw2
14 HTM · 10 STM · 24 QTM
rotationless
<R,D,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: Lw2 Dw 2R2 Dw' 2B2 Dw 2R2 Dw' 2B2 Lw2. Every algorithm above was run by our logic engine from that state and reaches "solved".