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Find the pair's shape as for F2L, then count the misoriented last-layer edges (a top edge whose top facet does not show the top colour).
Your status
Algorithms (7)
F' U2 F U' R U R'
My choice
7 HTM · 7 STM · 8 QTM
3-gen
rotationless
<U,R,F>
Cubemuch
y' R' U2 R y U' R U R'
7 HTM · 7 STM · 8 QTM
2-gen
rotation
oh
<U,R>
Cubemuch
y2 B' Lw' U' B U B' Lw U2 B
9 HTM · 9 STM · 10 QTM
3-gen
rotation
<U,L,B>
Cubemuch
x U' B' y B U' B' y' U B' U
8 HTM · 8 STM · 8 QTM
2-gen
rotation
<U,B>
Cubemuch
(U2) first, then:
R' U2 x' R2 U' R U x R U2 R
9 HTM · 9 STM · 12 QTM
2-gen
rotation
oh
<U,R>
Do U2 first (AUF) on the case as drawn. · Cubemuch
(U') first, then:
y' R' U2 R y2 U' x U R' U R U2
9 HTM · 9 STM · 11 QTM
2-gen
rotation
oh
<U,R>
Do U' first (AUF) on the case as drawn. · Cubemuch
y2 B' U2 B y2 B' y' U' B U B' y B
9 HTM · 9 STM · 10 QTM
2-gen
rotation
<U,B>
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: R U' R' U y' R' U2 R y. Every algorithm above was run by our logic engine from that state and reaches "f2l-eo".