ELS F6 (384)
HLS
0C1E
The source groups the cases by how many of the last layer's own corners (C) and edges (E), the pair aside, already show the top colour on top (3C3E: all of them); read that first, then the corners' top colours.
Your status
Algorithms (6)
R y U' R U2 x R2 U R U2
My choice
8 HTM · 8 STM · 11 QTM
2-gen
rotation
oh
<U,R>
One hand: R and U only
Cubemuch
y' B U' Rw B2 U B' U' Rw' U B'
10 HTM · 10 STM · 11 QTM
3-gen
rotation
<U,R,B>
One hand: needs L, B, S or E
Cubemuch
y' B U' Rw B U' Rw B Rw2 U B'
10 HTM · 10 STM · 11 QTM
3-gen
rotation
<U,R,B>
One hand: needs L, B, S or E
Cubemuch
y2 B' U2 Lw' B U' B U B' Lw B
10 HTM · 10 STM · 11 QTM
3-gen
rotation
<U,L,B>
One hand: needs L, B, S or E
Cubemuch
R y U' R U2 R' y2 U x' U2 R U R'
10 HTM · 10 STM · 12 QTM
2-gen
rotation
oh
<U,R>
One hand: R and U only
Cubemuch
x U' B' y U B' x2 U2 B U B' y2 U B
10 HTM · 10 STM · 11 QTM
2-gen
rotation
<U,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: B U' Rw U B U' B2 Rw' U B' y. Every algorithm above was run by our logic engine from that state and reaches "f2l-oll".